TUGAS KELOMPOK PERTEMUAN KE-2
Nama: Ananda Setiyaji NIM : 17220708 Kelas : 17.2B.05 1.) 192.168.10.1/30 Netmask = 255.255.0.0 Subnet = 11111111.11111111.11111111.11111100 Network = 2⁶ = 64 Host = 2²-2 = 2 Alokasi IP Network : 192.168.10.0 Host : 192.168.10.1 - 192.168.10.2 Broadcast : 192.168.10.3 2.) 172.168.10.1/16 Netmask = 255.255.000.000 Subnet = 11111111.11111111.00000000.00000000 Network = 2n = 1 Host = 2h - 2 = 216 - 2 = 65.534 Alokasi ip : Network : 172.168.0.0 Host : 172.168.0.1 - 192.168.255.254 Broadcast : 192.168.255.255 3.) 172.168.10.1/22 Netmask = 255.255.252.0 ...